Question

if initial charge on all capacitors were zero, work done by the battery in the circuit shown is

Answer 1

Given :

A circuit containing battery and capacitors .

To find :

The work done by the battery .

Solution :

Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2

=> net capacitance = 2 + 2

=> net capcaitance = 4 μF

Work done by the battery = ( 1 / 2 ) * C * V * V

=>  ( 1 / 2 ) * 4 * 1$0^{-6}$ * 10 * 10

=> 2 * 1$0^{-4}$ J

The work done by the battery is 2 * 1$0^{-4}$ J .