If initial charge on all the capacitors were zero,
work done by the battery in the circuit shown is
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Answer:
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Given :
Given :A circuit containing battery and capacitors .
Given :A circuit containing battery and capacitors .To find :
Given :A circuit containing battery and capacitors .To find :The work done by the battery .
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μF
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10=> 2 * 10^{-4}0
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10=> 2 * 10^{-4}0 −4
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10=> 2 * 10^{-4}0 −4 J
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10=> 2 * 10^{-4}0 −4 JThe work done by the battery is 2 * 10^{-4}0
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10=> 2 * 10^{-4}0 −4 JThe work done by the battery is 2 * 10^{-4}0 −4
Given :A circuit containing battery and capacitors .To find :The work done by the battery .Solution :Net capacitance = [( 4 * 4) / ( 4 + 4 )] + 2=> net capacitance = 2 + 2=> net capcaitance = 4 μFWork done by the battery = ( 1 / 2 ) * C * V * V=> ( 1 / 2 ) * 4 * 10^{-6}0 −6 * 10 * 10=> 2 * 10^{-4}0 −4 JThe work done by the battery is 2 * 10^{-4}0 −4 J .