Question

if initial speed is 2m/s and acceleration is 4m/s2 then displacement covered in the 5th second is 1)20m 2)21m 3)22m 4)23m

Answer 1

Answer:

Explanation:

u=2 m/s

a=4 m/s^2

t= 5 seconds

applying first equation

a=v-u/t

4=v-2/5

20+2=v

v=22 m/s

applying third equation

v^2 - u^2= 2as

(22)^2-(2)^2=2x 4 x s

484-4=8xs

s=480/8

s=60 metre

therefore total displacement is 60 metre,