Question

if initial velocity 5,acceleration=-2,find distance covered in 5th sec

Answer 1

Units of velocity and acceleration???
Let u = 5m/s and a = -2m/s^2
S = u + a(n - 1/2)
S = 5 + ((-2)(5 - 1/2))
S = -4 m

Distance = 4m

Answer 2

Answer:

Distance = 600 m.

Explanation:

Given -

• Initial Velocity(u) =5m/s
• Acceleration(a) = (-2)m/s²
• Time(t) =5 secs.

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To Find-

• Distance(s).

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Solution -

$\blue\bigstar$$\underbrace\mathscr\red{Finding\:Final\:Velocity(v)-}$

$\mapsto$ Formula-$\huge\mathbb\colorbox{black}{\color{white}{v=u+at}}$

$\mapsto$Answer- [after replacing values]

$\implies$ ㅤv=5+(-2)×5

$\implies$ㅤ v= 5(-10)

$\implies$ ㅤv= (-5)

ㅤ✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏

$\blue\bigstar$$\underbrace\mathscr\red{Finding\:Distance(s)-}$

$\mapsto$Formula -

$s = ut + \frac{1}{2} a {t}^{2}$

$\mapsto$ Answer -

$= (5 \times 5) + \frac{1}{2} ( - 2 ) \times {5}^{2} \\ \\ = 25 + ( - 1) \times 25 \\ \\ = 24 \times 25 \\ \\ = 600 \: m$

So, distance is 600 m.