Question

If initial velocity is 10m/sec and acceleration is -2m/sec^2. Then find the distance in 6 seconds.

Answer 1

Answer:

- 12 m

Explanation:

Given,

Initial velocity ( u ) = 10 m/s

Acceleration ( a ) = - 2 m/s²

Time ( t ) = 6 sec s

To find : Distance ( s ) = ?

By 2nd equation of motion,

s = ut + at²/2

= ( 10 ) ( 6 ) + ( - 2 ) ( 6² )

= 60 + ( - 72 )

= 60 - 72

s = - 12 m