if initial velocity is 7.time is 4 and displacement is 92 then find acceleration
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s=ut+ 1/2 at^2
s=92, u=7 , t=4 ,a=?
92= 7(4) + 1/2 × a × 4^2
92 =28 + 1/2 × a × 16
92= 28 + 8a
92-28=8a
8a=64
a=64/8
a=8m/sec^2 is the acceleration
s=92, u=7 , t=4 ,a=?
92= 7(4) + 1/2 × a × 4^2
92 =28 + 1/2 × a × 16
92= 28 + 8a
92-28=8a
8a=64
a=64/8
a=8m/sec^2 is the acceleration
Answered by
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HEY BUDDY...!!!!
HERE IS UR ANSWER....
___________________
▶️ Given
=> u ( initial velocity ) = 7 m / s
=> t ( time ) = 4 s
=> s ( displacement ) = 92 m
⏺️ First we'll find v ( final velocity )
=> velocity ( v ) = displacement ( s ) / time ( t )
=> velocity ( v ) = 92 / 4
=> velocity ( v ) = 23 m / s
⏺️ Using v = u + at
=> 23 = 7 + a . 4
=> 23 - 7 = 4 . a
=> 16 = 4 . a
=> a = 4 m / s^2
HOPE HELPED..
GOOD EVENING..
:-)
HERE IS UR ANSWER....
___________________
▶️ Given
=> u ( initial velocity ) = 7 m / s
=> t ( time ) = 4 s
=> s ( displacement ) = 92 m
⏺️ First we'll find v ( final velocity )
=> velocity ( v ) = displacement ( s ) / time ( t )
=> velocity ( v ) = 92 / 4
=> velocity ( v ) = 23 m / s
⏺️ Using v = u + at
=> 23 = 7 + a . 4
=> 23 - 7 = 4 . a
=> 16 = 4 . a
=> a = 4 m / s^2
HOPE HELPED..
GOOD EVENING..
:-)
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