Question

If initial velocity of an object is (2j^) m/s and it moves with constant acceleration (i^+j^) m/s?, then the velocity of particle at the end of 2 s is​

Answer 1

Hope it's helpful to you.

Please mark as Brainliest answer.

(•‿•)(・∀・)◉‿◉｡◕‿◕｡

Answer 2

velocity of particle at the end of 2 s is​ 2i^+ 4j^

Explanation:

acceleration = dv/dt  =  Change in velocity wrt time

acceleration = change in velocity / time

acceleration = ( Final velocity - Initial Velocity) / time

=>  i^+j^ = ( v  -  2j^)/ 2

=> 2i^+ 2j^  = v -  2j^

=> v = 2i^+ 4j^

velocity of particle at the end of 2 s is​ 2i^+ 4j^

Learn more:

The displacement s of a particle at a time t is given by s = t³ - 4t² - 5t ...

https://brainly.in/question/6533672

a particle starts fr rest and acceleration at any time is given by f-kt² ...

https://brainly.in/question/18188570