Question

If initial velocity of an object is zero, then distance covered by it in time t and acceleration of 9.8 m s-2 would be A. 2.9 t2 B. 3 t2 C. 4 t2 D. 4.9 t2

Answer 1

Answer:

D) 4.9 t^2

Explanation:

u = 0 m/s , a = 9.8 m/s^2

By second kinematic equation,

s = ut + 0.5 at^2

s = 0×t + 0.5 × 9.8 t^2

s = 4.9 t^2

Hope it helps