If initial velocity of projectile be doubled kepping anglke of projection same then maximum height reach will be
Answers
Answered by
1
4 times dddfffgggfffjvtivtitkggk
Answered by
0
Max H =u^2sin^2 theta /2g
Here angle is same in both case therefor
And u'=2u
H' = 4H
Here angle is same in both case therefor
And u'=2u
H' = 4H
Similar questions
Physics,
6 months ago
English,
6 months ago
Math,
11 months ago
Social Sciences,
1 year ago
Math,
1 year ago