Question

if,int i=10,j=20,find s
while (i <=50)
{
i=i+10;
}
s=s+i+j;
System.out.println ("Sum="+s);​

Answer 1

Answer:

s = 80

Explanation:

u will get an error because without initializing s u can't add it with i and j

in s = s+i+j , so

first of all u have to initialize int s = 0 because without that the program will not run.Take care that their are no spaces

the correct program is like this :

public class s

{

   public static void main(String []args)

   {

     int i=10,j=20,s=0;

     while (i <=50)

     {

       i=i+10;

     }

     s=s+i+j;

     System.out.println("Sum="+s);

   }

}

and then it will compile and when we will run it it will the output as:

sum = 80

Hope it helps!

plz mark me as brainliest if it helps you!

Answer 2

Question:-

Write the output of the following code.

Solution:-

Given code,

int i=10,j=20,s;

while (i <=50)

{

i=i+10;

}

s=s+i+j;

System.out.println ("Sum="+s);

After completion of loop, the value of i will be,

60

s=0+60+20=80

Now, s gets printed.

Output:-

80