If intgrate root 2x+3/x^2-5x+6dx=Aln|x-3|+Bln|x-2|+C then A+B=?
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HELLO DEAR,
GIVEN:-
solving by partial fraction,
(2x + 3)/(x² - 5x + 6) = (2x + 3)/(x² - 2x - 3x + 6)
=> (2x + 3)/(x - 2)(x - 3) = A'/(x - 2) + B'/(x - 3)
=> 2x + 3 = A'(x - 3) + B'(x - 2)
=> 2x + 3 = x(A' + B') + (-3A' - 2B')
ok comparing both side like power of x,
A' + B' = 2 , 3A' + 2B' = -3
on solving we get,
A' = -7 , B' = 9
now,
on comparing LHS , RHS we get,
A = 9 , B = -7
so, A + B = 9 - 7 = 2
I HOPE IT'S HELP YOU DEAR,
THANKS
GIVEN:-
solving by partial fraction,
(2x + 3)/(x² - 5x + 6) = (2x + 3)/(x² - 2x - 3x + 6)
=> (2x + 3)/(x - 2)(x - 3) = A'/(x - 2) + B'/(x - 3)
=> 2x + 3 = A'(x - 3) + B'(x - 2)
=> 2x + 3 = x(A' + B') + (-3A' - 2B')
ok comparing both side like power of x,
A' + B' = 2 , 3A' + 2B' = -3
on solving we get,
A' = -7 , B' = 9
now,
on comparing LHS , RHS we get,
A = 9 , B = -7
so, A + B = 9 - 7 = 2
I HOPE IT'S HELP YOU DEAR,
THANKS
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