Question

If ionisation energy of hydrogen atom is 13.6 eV. I.E. of 1
Li+2 will be -
1) 13.6 eV 2) 10.4 eV 3) 40.8 eV 4) 122.4 eV​

Answer 1

Explanation:

Bohrs model can be helpful in this

according to this E= -13.6* z2/n2

so, in this the E is equal to energy of electron in the shell of atom whose atomic number is Z .

now same amount of energy with opposite sign must be given to electron in order to remove it.

I.E.=13.6 Z2 ev

since for lithium, z= 3

therefore you get l.e = 122.4 .ev

Answer 2

Answer:

atomic no of Li = 3

z = 3 ,

n is shell no.

and shell no. =1 in this question

I hope it helps you ✌