Question

if ionisation potential of H atom is 7.2x then energy difference between 2 amd 3 shell will be??

Answer 1

hey mate
here's the solution

Answer 2

Let E1, E2 and E3 be the first second and third shell respectively.

E1= - Ionisation Potential (I.P) = - 7.2x

En= E1/n^2

Therefore,

E2= - 7.2x / 4

Similarly,

E3= - 7.2x / 9

E3-E2= +7.2x/4 - (7.2x/9)

= 7.2x(1/4-1/9)

={(7.2x) (5)} /36

= x