Question

If IP of Li is 540 KJ/mol then energy required
to convert 1.0 gm of Li in Li+ it will be :
(1) 77 KJ
(2) 540 KJ
(3) 180 KJ
(4) 230 kJ​

Answer 1

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Answer 2

Answer :

Ionization enthalpy of Li = 540 kJ/mol

We have to find energy required to convert 1gm of Li into Li(+)$.$

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◈ Ionization enthalpy is defined as the energy required to remove the most loosely bound electron from an isolated gaseous atom.

ATQ,

Energy required to convert 1 mol (7g) of Li into Li(+) = 540 kJ

Hence, Energy required to convert 1g of Li into Li(+) will be

• 1×540/7 = 77 kJ

Option-A is the correct answer.