If is a complex cube root of unity then (3 + 3 + 5 + (2 + 6 + 6 (a) 0 (b) 8 (c) 64 (d) 128 .
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Step-by-step explanation:
(1−w+w
2
)
6
+(1+w−w
2
)
6
=[(1+w
2
)−w]
6
+[(1+w)−w
2
]
6
=[−w−w]
6
+[−w
2
−w
2
]
6
=(−2w)
6
+(−2w
2
)
6
=2
6
(w
6
+w
12
)
=2
6
(2)
=2
7
=128
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