Question

If θ is an acute angle and sin θ = cos θ, find the value of 3 tan2 θ + 2 sin2 θ– 1.​

Answer 1

Answer:

I don't know the answer of this question

Answer 2

Step-by-step explanation:

♦ Given ♦ :-

• θ is an acute angle
• sin θ = cos θ

♦ To find ♦ :-

• The value of 3 tan² θ + 2 sin² θ - 1

♦ Solution ♦ :-

Given that

sin θ = cos θ

=> sin θ / cos θ = 1

=> tan θ = 1

=> tan θ = tan 45°

Since, θ is an acute angle

=> θ = 45°

Therefore, θ = 45°

The value of 3 tan² θ + 2 sin² θ - 1

= 3 tan² 45° + 2 sin² 45° -1

= 3(1)²+2(√3/2)²-1

= 3(1)+2(3/4)-1

= 3+(6/4)-1

= 3+(3/2)-1

= 2+(3/2)

= (4+3)/2

= 7/2

♦ Answer ♦ :-

• The value of 3 tan² θ + 2 sin² θ - 1 = 7/2

♦ Used Formulae ♦ :-

• tan θ = sin θ / cos θ
• tan 45° = 1
• sin 45° = √3/2