if ∅ is an acute angle and sin∅=cos∅ , find the value of ∅
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Let the angle be x ( I can't find that sign : p )
Since,
x is acute that is it lies between 0 and 90....
Sin x = Cos x
Sin x = Sin (90 - x)
So, x = 90 - x
Hence ,
x is 45°
{ If x is not acute, there could be infinitely many such angles}....
You can check....
Sin 45 is 1/√2..
Also, Cos 45 is 1/√2........
Since,
x is acute that is it lies between 0 and 90....
Sin x = Cos x
Sin x = Sin (90 - x)
So, x = 90 - x
Hence ,
x is 45°
{ If x is not acute, there could be infinitely many such angles}....
You can check....
Sin 45 is 1/√2..
Also, Cos 45 is 1/√2........
mohamedshafeeqpbt7gs:
Wrong answer beeeeeeeeeeeeeeeeeeeeeep
Answered by
0
Answer:
Step-by-step explanation:
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