If is an acute angle and sin cose, then the value of
2 tan 0 cose-2 is
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Step-by-step explanation:
sinθ=cosθ
cosθ
ssin =cosθ
ccos
tanθ=1=tan45 o
θ=45 o
Therefore, 2tan
θ
+sin
2
θ−1=2tan
45o+sin2
45o−1=2×(1)
2+( 2
1) 2−1=2+
2
1−1=2
3
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