if Φ is an acute angle and tanΦ + cotΦ=2,find the value of tan^5Φ+cot^5Φ
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4
Answer:
the answer is 2
Step-by-step explanation:
refer to the above attachment for the solution
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2
Answer:
tan∅ + cot∅ = 2
=> tan∅ + con∅ = 1 + 1
on comparing both sides
tan∅ = 1 and cot ∅ = 1
=> tan ∅ = tan45 and cot∅ = cot45
=> ∅ = 45 and ∅ = 45
thus,
∅ = 45°
now,
tan^5 ∅ + cot^5 ∅
=( tan45)^5 +( cot45)^5
= 1^5 + 1^5
= 1 + 1
= 2.
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