Question

If # is an operation such that for any integers a
and b, we have: a#b= a × b-
2 × a × b + b × b (-a)×b+b×b
then find (a)4#(-3) (b)(-7)#(-1).

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Answer 1

Step-by-step explanation:

Given, a∗b=a×b+(a×a+b×b)

So.

(i)

we put a=(−3) and b=(−5)

(−3)∗(−5)=(−3)×(−5)+[(−3)×(−3)+(−5)×(−5)]

=15+(9+25)=15+34=49

(ii)

Similarly, a=−6,b=2

(−6)∗2=(−6)×2+[(−6)×(−6)+2×2]

=−12+(36+4)

=−12+40=28