Question

if ∆ is an operation such that for integer a and b . we have a ∆ b = a× a - 2×a×b+b×b. then find the value of 4 ∆ ( - 3 )​

Answer 1

Step-by-step explanation:

aΔb=a×b−2×a×b+b×b(−a)×b+b×b

So,

i. 

4Δ(−3)=[4×(−3)]−[2×4×(−3)]+[(−3)×(−3)(−4)×(−3)]+[(−3)×(−3)]

=[−12]−[−24]+[108]+[9]

=−12+24+108+9

=−12+141

=129

ii. 

(−7)Δ(−1)=[(−7)×(−1)]−[2×(−7)×(−1)]+[(−1)×(−1)(7)×(−1)]+[(−1)×(−1)]

=7−14+[−7]+1

=7−14−7+1

=8−21

=−13

Now (−3)Δ4=[(−3)×4]−[2(−3)×4]+[4×4(3)×4]+[4×4]

=−12+24+192+16

=−12+232

=22