if is equal to 5 + 2 under root 6 and b is equal to 1 upon 8 then what will be the value of a square + b square
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If a= 5+2√6
and b=1/8
Then a^2+b^2= (5+2√6)^2+(1/8)^2
= ( 25+24+20√6)+(1/64)
=(49+20√6)+1/64
=(49*64+20*64*√6+1)/64
=(3136+1280√6+1)/64
=( 3137+1280√6)/64
and b=1/8
Then a^2+b^2= (5+2√6)^2+(1/8)^2
= ( 25+24+20√6)+(1/64)
=(49+20√6)+1/64
=(49*64+20*64*√6+1)/64
=(3136+1280√6+1)/64
=( 3137+1280√6)/64
Anonymous:
is it right
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