if is the zeros quadratic polynomial
x² + (a+1)x + b are
2 and - 3
then a = ? b = ?
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5
Answer:
a=(0) and b=(-6)
Step-by-step explanation:
Bro you may know that the standard form of quadratic equation is ax²+bx+c
If the roots of this equation are x and y,then the sum of roots,i.e.x+y=-b/a.....and the product of rootsi.e.x*y=c)a.
Therefore x+y=(2)+(-3)=(-1)=[-(a+1)]
So a=+0)
Similarly,x*y=(2)*(-3)=(-6)=b/1
So b=(-6)
Thanks bro.
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