If iso butane and n-butane are present in a gas then how much oxygen should be required for complete combustion of 5 kg of this gas
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Isobutane and n-Butane have same chemical formula (C4H10)(C4H10) and give same combustion reaction.
2C4H10+13O2→8CO2+10H2O2C4H10+13O2→8CO2+10H2O
This means 2 moles of this mixture requires 13 moles of oxygen.
Molecular mass of butane=58g/mol58g/mol
Molecular mass of oxygen=32g/mol32g/mol
Moles of butane in 10kg=10∗100058=10000∗1358∗210kg=10∗100058=10000∗1358∗2moles of O2O2=130000∗32116g=130000∗32116g O2=130∗32116kgO2=130∗32116kg O2O2.
Therefore, 35.862 kg oxygen is used.
2C4H10+13O2→8CO2+10H2O2C4H10+13O2→8CO2+10H2O
This means 2 moles of this mixture requires 13 moles of oxygen.
Molecular mass of butane=58g/mol58g/mol
Molecular mass of oxygen=32g/mol32g/mol
Moles of butane in 10kg=10∗100058=10000∗1358∗210kg=10∗100058=10000∗1358∗2moles of O2O2=130000∗32116g=130000∗32116g O2=130∗32116kgO2=130∗32116kg O2O2.
Therefore, 35.862 kg oxygen is used.
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