Question

If iso butane and n-butane are present in a gas then how much oxygen should be required for complete combustion of 5 kg of this gas

Answer 1

Isobutane and n-Butane have same chemical formula (C4H10)(C4H10) and give same combustion reaction.

2C4H10+13O2→8CO2+10H2O2C4H10+13O2→8CO2+10H2O

This means 2 moles of this mixture requires 13 moles of oxygen.

Molecular mass of butane=58g/mol58g/mol

Molecular mass of oxygen=32g/mol32g/mol

Moles of butane in 10kg=10∗100058=10000∗1358∗210kg=10∗100058=10000∗1358∗2moles of O2O2=130000∗32116g=130000∗32116g O2=130∗32116kgO2=130∗32116kg O2O2.

Therefore, 35.862 kg oxygen is used.