If it is a rhombus .Find x and y .pls show step by step
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hey there ,,
as we know that rhombus bisects each other at 90° .
than ,
angle x = 90°
let the angle beside x be w
therfore ,
angle x + angle w = 180° (by linear pair )
therefore angle w = 90°
now we know that sum of all angles of a triangle is = 180°
let the other angle be z of the triangle
therefore ,
90° + 68° + z = 180°
z = 12°
now ,
we know that opposite sides are parallel of a rhombus
therefore ,
angle z = angle y ( by alternate interior angles )
angle y = 12°
hence angle x = 90° and angle z = 12°
hope it helps !!!
be brainly ♥♥
as we know that rhombus bisects each other at 90° .
than ,
angle x = 90°
let the angle beside x be w
therfore ,
angle x + angle w = 180° (by linear pair )
therefore angle w = 90°
now we know that sum of all angles of a triangle is = 180°
let the other angle be z of the triangle
therefore ,
90° + 68° + z = 180°
z = 12°
now ,
we know that opposite sides are parallel of a rhombus
therefore ,
angle z = angle y ( by alternate interior angles )
angle y = 12°
hence angle x = 90° and angle z = 12°
hope it helps !!!
be brainly ♥♥
Answered by
0
Let abcd be a rhombus
with angle c = 68 degrees
angle a = y
we know that diagonals of a rhombus are perpendicular bisector
I.e ad and bc bisect at 90 degrees
therefore,
x =90 degrees ..............( 1 )
diagonals intersect at point o
hence,
AB and CD are parallel lines with bc as the transversal
therefore,
angel OCD = angel OBA = 68 degrees ...............( 2 )
Now, in triangle ABO
angle A + angle B + angle O = 180 degrees ( Angle Sum Property)
y + 68 + 90 = 180 degrees ( 1 and 2 )
y + 158 = 180
y = 180 - 158 ( transposing 158 to RHS )
y = 22 degrees
Answer : x = 90 degrees and
y = 22 degrees.
with angle c = 68 degrees
angle a = y
we know that diagonals of a rhombus are perpendicular bisector
I.e ad and bc bisect at 90 degrees
therefore,
x =90 degrees ..............( 1 )
diagonals intersect at point o
hence,
AB and CD are parallel lines with bc as the transversal
therefore,
angel OCD = angel OBA = 68 degrees ...............( 2 )
Now, in triangle ABO
angle A + angle B + angle O = 180 degrees ( Angle Sum Property)
y + 68 + 90 = 180 degrees ( 1 and 2 )
y + 158 = 180
y = 180 - 158 ( transposing 158 to RHS )
y = 22 degrees
Answer : x = 90 degrees and
y = 22 degrees.
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