Question

if it is an ap find out the common difference is a + b ,(a+1)+b,(a+1)+(b+1),(a+2),+(b+1),(a+2)+(b+2).​

Answer 1

Answer:

1

Step-by-step explanation:

since the given progression is an AP

=> common difference

d = second term- first term..............(1)

d =third term- second term.............(2)

d= [ (a+1)+b - (a+b)]= [ a+1+b-a-b] = 1......from(1)

d= [{ (a+1)+(b+1)} - { (a+1)+b}]

= [ a+b+2-a-1-b] = 2-1= 1..........from (2)

hence, common difference = 1