Question

if it is given (2^x) - (2^(x-1)) =4 then what is the value of x^x​ ?

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Answer 1

Answer:

${x}^{x} = 27$

Step-by-step explanation:

${2}^{x} - {2}^{x - 1} = 4 \\ \\ \therefore {2}^{x - 1} (2 - 1) = 4 \\ \\ \therefore {2}^{x - 1} (1) = 4 \\ \\ \therefore {2}^{x - 1} = 4 \\ \\ \therefore {2}^{x - 1} = {2}^{2} \\ \\ \therefore \: x - 1 = 2 \\ \\ \therefore \: x = 2 + 1 \\ \\ \therefore \: x = 3 \\ \\ = > \: now \: we \: find \: to \: {x}^{x} \\ \\ = > {x}^{x} \\ \\ = > {3}^{3} \\ \\ = > 27$