If it is given that object is moving with velocity 20m/s than it is initial velocity or final velocity
Answers
Answered by
3
Answer:
Applied force
F
(
t
)
=
(
−
22.0
m
−
233.7
m
t
)
N
Explanation:
Initial velocity
u
=
20
m
s
−
1
. Final velocity
v
=
0
, distance traveled
=
4
m
.
The applicable kinematic equation for a constant acceleration is
v
2
−
u
2
=
2
a
s
⇒
0
2
−
20
2
=
2
a
×
4
⇒
a
=
−
400
8
=
−
50
m
s
−
2
Let us find out for what time this retarding force is applied.
Using the other kinematic equation
v
=
u
+
a
t
we get
0
=
20
+
(
−
50
)
t
t
=
20
50
=
0.4
s
We see that the object takes more time than given in the question to come to stop. This implies that it is not a case of constant deceleration.
Explanation:
Similar questions