Question

If it is possible to project a particle with a given velocity in two possible ways so as to make it pass through a point at a distance (r) from the point of projection.The product of the time taken to reach this point in the two possible ways is then proportional to​

Answer 1

Answer:

tan∅

Explanation:

Let u be the initial velocity of projection ∅=theta

T=$\frac{T=2usintheta}{g}$

if the particle reaches the same point at a distance R thrown wit a same initial velocity the particle is thrown at complementary angles from the horizontal

ie the particle is thrown at angle ∅ and (90-∅)

∴ $T_{1}= \frac{2usintheta}{g} \\\\T_{2}=\frac{2usin(90-theta)}{g}$........(1)

∵Sin(90-∅)=cos∅...... (2)

∵$\frac{sintheta}{costheta}$ = tan∅........(3)

so, from 1 2 & 3,

∴$\frac{T_{1} }{T_{2} }$= tan∅

Answer 2

Answer:

sahiluday436

Explanation:

your answr is conforlmy wrong