If it takes a force of 20N to stretch a spring of 0.1m how much energy does the spring have
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The energy stored in the spring would be 1 joule.
Explanation:
When a spring is stretched by a force then energy is stored in that spring. In this particular question we are going to find energy stored in spring on which 20N force is applied and it is stretched by 0.1m.
According to Hook’s Law:
F = Kx
Where K is spring constant.
K = 20/0.1 = 200 Nm^(-1 )
We know that:
W = ½ Kx^2
W = ½ (200) (0.1)^2
W= 1 J
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