If it takes two pipes a and b 12 hours and 15 hours respectively to fill a tank can empty the tank in 10 hours if all the three pipes are opened simultaneously in how much time will the tank be full
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Answer:
20 hrs
Step-by-step explanation:
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Answer:
Time taken by pipe 2 to fill the tank =12hours
Step-by-step explanation:
so by pipe 2 in one hour 12 th part of the tank is filled Time taken pipe 3 to empty the tank= 20hours so by 3 in one hour 1/20 th part of the tank is filled
when three pipes are operated simultaneously Amount of water present in the tank per hour=water entered into the tank -water left from the tank Amount of water present in the tank per hour= 1/10+1/12=22/12-1/20=(22-6)/120=16/120=2/15 2/15 th part of the tank is filled in one hour So total time taken to fill the tank by using 3 pipe s is 15/2 hours=7 h 30 min
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