Question

If it took a bulldozer 567.8 joules of work to push a mound of dirt 30.5m.how much force did the bulldozer have to apply?

Answer 1

Given:-

• Work Done = 567.8J

• Displacement = 30.5m

To Find:-

• The Force did the bulldozer have to apply?

Formulae used :-

• w = F × s

Where,

• F = Force
• s = Displacement
• w = Work done

Now,

→ w = F × s

→ 567.8 = F × 30.5

→ 567.8 = 30.5F

→ F = 567.8/30.5

→ F = 18.61N

Hence, The force bulldozer applied is 18.61N

EXTRA INFORMATION:-

• Work done is defined as when a force Displaces body in it's own Direction or opposite.

• When a body is moving with some Velocity, it is said to have kinetic energy.

• The energy Possessed by object in its virtue of Position is Potential energy.

Answer 2

Answer:

✪ Given :-

• A bulldozer 567.8 J of work to push a mound of displacement 30.5 m.

✪ To Find :-

• How many force did the bulldozer have to apply.

✪ Formula Used :-

$\boxed{\bold{\large{Work\: =\: Force\: ×\: Displacement}}}$

✪ Solution :-

Given :-

• Work Done = 567.8 J
• Displacement = 30.5 m

➣ According to the question by using the formula we get,

⇒567.8 = F × 30.5

⇒567.8 = 30.5F

⇒F = $\sf\dfrac{\cancel{567.8}}{\cancel{30.5}}$

➙ F = 《 18.61 N 》

$\therefore$ The force applied by bulldozer is 18.61 N.

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