if it was a Friday on 4th May 1956 then what was the day on 6th july 1957
please answer correctly fast
Answers
Answered by
2
Answer:
Friday
Given year 1985 is non-leap year and 8 March 1985 of the year was Friday.
Let us find the number of odd days between 8 Mar and 26 July.
Month Mar Apr May Jun July
Days 23(=31 -8) + 30 + 31 + 30 + 26 = 140 days or 20 weeks
So, the day on 26th July will be the same as the day on 8 March i.e., Friday.
Hence, option (B) is the correct answer.
Answered by
0
Answer:
Saturday,6th July 1957
Step-by-step explanation:
have a great day
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