If Ixy is the moment of inertial of a ring
about a tangent in the plane of the ring Ix'y'
is the moment of inertia of a ring about a
tangent perpendicular to the plane of the
ring then
(A) Ixy = Ix'y' (B) Ixy = 1/2 Ix'y'
(C) Ix'y' = 3/4 Ixy (D) Ixy = 3/4 Ix'
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Answer:
The tangent to the ring in the plane of the ring is parallel to one of the diameters of the ring. The distance between these two parallel axes is R, the radius of the ring. Using the parallel axes theorem,
Itangent=Idia+MR2=2MR2+MR2=23MR2.
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