Question

If jake travelled at three-fifth of his usual speed , he would reach his destination 30 minutes late . By how many minutes would he be early . If he traveled at 5/3 of his usual speed

options
1 . 12
2 . 18
3 . 16
4 . 14​

Answer 1

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Answer:

12

Step-by-step explanation:

12

Answer 2

Answer:

Jake would reach 18 minutes early if he travelled at $\frac{5}{3}$ of his usual speed.

Step-by-step explanation:

Let the usual speed of Jake to travel be $x$ and the usual time taken by jake be $y$.

Let the time taken if he travelled at $\frac{5}{3}$ of his speed be $y'$.

We know that the distance covered is the product of the speed with the time taken to cover the distance. So, the distance Jake travels will be equal to:

$d=xy$  

Now, if Jake travels at three-fifth of his usual speed, the time taken will be $\frac{5}{3}$ of the usual time as the distance remains the same.

It means that the extra time taken will be $\frac{2}{3}$, i.e., 30 minutes,

Representing this mathematically, we get:

$\frac{2}{3}y=30$

or we can say:

$y=45\ min$                              ...(i)

Now, if Jake travels at  $\frac{5}{3}$ of his usual speed, the time taken will be  $\frac{3}{5}$ of the usual time taken. Representing this mathematically, we get:

$\frac{3}{5}y=y'$

Substituting (i), we get:

$\frac{3}{5}(45)=y'$

or we can say:

$y'=27$

The time by which Jake would reach early will be: $45-27=18$

So, Jake will reach 18 mins early if he travels at $\frac{5}{3}$ of his usual speed.