Question

If Jhanavi borrowed Rs.1,25,000 at 8% compounded, what will be the amount to be paid back at the end of 2 years?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Amount=1,45,800\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given:}} \\ \tt: \implies Principal(p)= 125000 \: rupees \\ \\ \tt: \implies Rate(r) = 8\% \\ \\ \tt: \implies Time(t) = 2 \: years \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Amount(A) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A = p(1 + \frac{r}{100} )^{t} \\ \\ \tt: \implies A = 125000(1 + \frac{8}{100})^{2} \\ \\ \tt: \implies A= 12500 \times (\frac{100 + 8}{100} )^{2} \\ \\ \tt: \implies A = 125000 \times \frac{(108)^{2} }{10000} \\ \\ \tt: \implies A= 12.5 \times 108 \times 108 \\ \\ \green{\tt: \implies A= 1,45,800 \: rupees}\\\\ \green{\tt\therefore Jhanavi\:had\:to\:pay\:1,45,800\:rupees}\\\\ \:\:\green{\tt\:the\:end\:of\:2nd\:year.}$

Answer 2

Answer:

The amount Jahanvi will pay back Rs. 1,45,800 at the end of 2 years.

Step-by-step explanation:

Given :

Jahanvi borrowed = Rs. 1,25,000

Rate = 8%

Time = 2 years

To find :

The amount she'll get

Solution :

Here -

• P = 1,25,000
• R = 8
• N = 2

${\boxed{\sf{A= P\left( 1 + \frac{R}{100}\right)^{N}}}}$

$\sf{\longrightarrow} \: A= 125000\left( 1 + \dfrac{8}{100}\right)^{2} \\ \\ \sf{\longrightarrow} \: A=125000\left( \frac{108}{100}\right)^{2} \\ \\ \sf{\longrightarrow} \: A=125000 \times \dfrac{27}{25} \times \dfrac{27}{25} \\ \\ \sf{\longrightarrow} \: A=200 \times 27 \times 27 \\ \\ \sf{\longrightarrow} \: A=5400 \times 27 \\ \\ \sf{\longrightarrow} \: A=145800$

Amount = Rs. 1,45,800

$\therefore$ The amount Jahanvi will pay back Rs. 1,45,800 at the end of 2 years.