Question

if jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes ,how many possibilities can he dress himself up for the day?

Answer 1

Thank you for asking this question.

The answer to this question is 216.

In case if each outfit has a t-shirt in it a pair of pants and also a pair of shoes.

So for the different possibilities, there are:

12 x 6 x 3 = 216

So there are 216 different possibilities he can dress himself up for the day.

I hope this answer helps you.

Answer 2

Answer:

216

Step-by-step explanation:

Given :  jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes

To Find: how many possibilities can he dress himself up for the day?

Solution:

In case if each outfit has a t-shirt in it a pair of pants and also a pair of shoes.

We will use combination .

Number of possibilities = $^{12}C_1 \times ^6C_1 \times ^3C_1$

                                      = $\frac{12!}{1!(12-1)!} \times \frac{6!}{1!(6-1)!} \times \frac{3!}{1!(3-1)!}$

                                      = $\frac{12!}{1!(11)!} \times \frac{6!}{1!(5)!} \times \frac{3!}{1!(2)!}$

                                      = $12 \times 6 \times 3$

                                      = $216$

So there are 216 different possibilities he can dress himself up for the day.