If k+1=²( 1+sin)(1-sin ) ,then find the value of k
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Answered by
2
Step-by-step explanation:
sec
2
θ(1+sinθ)(1−sinθ)=k+1
sec
2
θ(1−sin
2
θ)=k (a+b)(a−b)=a
2
−b
2
sec
2
θcos
2
θ=k
cos
2
θ
1
.cos
2
θ=k
k=1
Hope its help..
Answered by
2
Step-by-step explanation:
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