Question

if(k+1,2k+1) is an solution of linear equation 2x-3y=11 find the value of k​

Answer 1

Answer:

The value of k is equal to -3

Answer 2

The value of k is -3.

Step-by-step explanation:

Given : If $(k+1,2k+1)$ is an solution of linear equation $2x-3y=11$.

To find : The value of k ?

Solution :

If $(k+1,2k+1)$ is an solution of linear equation $2x-3y=11$ then the point satisfy the equation.

$2(k+1)-3(2k+1)=11$

$2k+2-6k-3=11$

$-4k=11+1$

$-4k=12$

$k=-\frac{12}{4}$

$k=-3$

Therefore, the value of k is -3.

#Learn more

Find the value of k, if (2,1) is a solution of the equation 2x+3y=k

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