Question

if k-1 ,4,k+3 are in ap find k
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Answer 1

Answer:

k=3

By,(First term)+(Third term)=($econd term/2)

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Answer 2

Answer:

Valueofk=2

Step-by-step explanation:

\begin{lgathered}k-3,\:2k+1\:and\:4k+3\:are\\the\:three\: consecutive\:terms\\of\:A.P\end{lgathered}

k−3,2k+1and4k+3are

thethreeconsecutiveterms

ofA.P

\begin{lgathered}we\: know\:that,\\If\:a,b,\:and\:c \:are \: in \:A.P\\\:then\\b-a=c-b\end{lgathered}

weknowthat,

Ifa,b,andcareinA.P

then

b−a=c−b

\begin{lgathered}Here,\\(2k+1)-(k-3)=(4k+3)-(2k+1)\end{lgathered}

Here,

(2k+1)−(k−3)=(4k+3)−(2k+1)

\implies 2k+1-k+3=4k+3-2k-1⟹2k+1−k+3=4k+3−2k−1

\implies k+4=2k+2⟹k+4=2k+2

\implies 4-2=2k-k⟹4−2=2k−k

\implies 2=k⟹2=k