Math, asked by lakshman1224, 4 months ago

If k+1, 4k-6 and 3k-2 are three consecutive terms of an A.P., then write the value of k.

Answers

Answered by janhavimudaliar100

2

Answer:

4k-6=3k-2

4k-3k= -2+6

1k= -8

k=-8

Answered by anwesha476

0

Answer:

I hope this will help you .

hey the above answer is wrong.

my answer is correct

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