Question

if k+1,4k-8, 3k-1 are in A.P then k=

Answer 1

Answer:

k=4

Step-by-step explanation:

As per AP, the difference between terms is equal. So,

4k-8-(k+1)=3k-1-(4k-8)

3k-9=7-k

4k=16

k=4

Answer 2

Given

K + 1, 4K -8, 3K - 1 are in AP

SOMETHING YOU NEED TO KNOW

If a, b and c are 3 numbers in an AP, then it has a common difference between them.

=> c - b = b - a

=> -b - b = -a- c

=> 2b = a + c

$\implies 2(4k-8) = 3k-1+k+1\\\implies 8k-16 = 4k\\\implies 8k-4k = 16\\\implies 4k = 16\\\implies k = 4$

$\boxed{\boxed{\bold{Therefore, \ the \ value \ of \ k \ is \ 4}}}}$