If k + 1, 8, k + 9 are three consecutive terms of an A.P., then k =
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Since these terms are consecutive terms of an A.P., the middle term must be the average of the other two.
⇒(k−3)+(4k+3)=2(2k+1)
⇒5k=4k+2
⇒k=2
Thus, the required value of k is 2.
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