if k-1, k+1 and 2k+3 are A.p the value ok k is
Answers
Answered by
6
Explanation:
k-1,k+1,2k+3 in AP
=2k+3-k-1=k+1-k+1
=k+2=2
=k=0
Answered by
2
Answer:
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Given AP terms,
- k - 1
- k + 1
- 2k + 3
Let,
- a1 = k - 1
- a2 = k + 1
- a3 = 2k + 3
To find common difference (d)
⟹ a2 - a1 = a3 - a2
➡ (k + 1) - (k - 1) = (2k + 3) - (k + 1)
➡ k + 1 - k + 1 = 2k + 3 - k - 1
➡ 2 = k + 2
➡ k = 2 - 2
➡ k = 0
Therefore, the value of k is " 0 ".
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Explanation:
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