English, asked by sreepriyakj676, 8 months ago

if k-1, k+1 and 2k+3 are A.p the value ok k is​

Answers

Answered by HeroicGRANDmaster
6

Explanation:

k-1,k+1,2k+3 in AP

=2k+3-k-1=k+1-k+1

=k+2=2

=k=0

Answered by Anonymous
2

Answer:

Given AP terms,

  • k - 1
  • k + 1
  • 2k + 3

Let,

  • a1 = k - 1
  • a2 = k + 1
  • a3 = 2k + 3

To find common difference (d)

a2 - a1 = a3 - a2

(k + 1) - (k - 1) = (2k + 3) - (k + 1)

k + 1 - k + 1 = 2k + 3 - k - 1

2 = k + 2

k = 2 - 2

k = 0

Therefore, the value of k is " 0 ".

Explanation:

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