Question

if k-1, k+1 and 2k+3 are A.p the value ok k is​

Answer 1

Explanation:

k-1,k+1,2k+3 in AP

=2k+3-k-1=k+1-k+1

=k+2=2

=k=0

Answer 2

Answer:

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Given AP terms,

• k - 1
• k + 1
• 2k + 3

Let,

• a1 = k - 1
• a2 = k + 1
• a3 = 2k + 3

To find common difference (d)

⟹ a2 - a1 = a3 - a2

➡ (k + 1) - (k - 1) = (2k + 3) - (k + 1)

➡ k + 1 - k + 1 = 2k + 3 - k - 1

➡ 2 = k + 2

➡ k = 2 - 2

➡ k = 0

Therefore, the value of k is " 0 ".

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Explanation:

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