Question

If k-1, k+1 and 2k+3
are in AP, then the value
of k is​

Answer 1

Answer:

AP is 2b = a + c

then ,

2 (k+1 )= 2k +3 +k-1

2k+2 = 3k +2

therefore k = 0

Answer 2

If k - 1 , k + 1 and 2k + 3 are in AP then the value of k is 0

Given : k - 1 , k + 1 and 2k + 3 are in AP

To find : The value of k

Concept :

If a , b , c are in AP then 2b = a + c

Solution :

Step 1 of 2 :

Write down the given data

Here it is given that k - 1 , k + 1 and 2k + 3 are in AP

Step 2 of 2 :

Find the value of k

Since k - 1 , k + 1 and 2k + 3 are in AP

$\displaystyle \sf{ 2(k + 1) = (k - 1) + (2k + 3)}$

$\displaystyle \sf{ \implies 2k + 2=3k + 2}$

$\displaystyle \sf{ \implies 2k - 3k = 2 - 2}$

$\displaystyle \sf{ \implies k = 0}$

Hence the required value of k = 0

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