Question

If k-1 , k+1 and 2k+3 are three consecutive terms of an AP ,then the value of k is

Board:CBSE
Chapter: Arithematic Progression
Class: 10

Answer 1

Answer:

The value of k is 3.

Step-by-step explanation:

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Answer 2

If a,b, c are in Ap

b-a = c-b-----(1)

According to the given problem

a=k, b=2k-1, c=2k+1

Using (1)

(2k-1) - k = (2k+1)-(2k-1)

2k-1-k =2k+1-2k+1

k-1 = 2

k=2+1

k=3