If K ‐ 1, K+3 and 3K ‐ 1 are in Ap,then find the value of K
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Answered by
7
They are in Ap so
2(k + 3) = k -1 + 3k -1
2k + 6 = 4k -2
2k - 4k = -2 -6
-2k = -8
k = 4
Answered by
0
Answer:
K = 4
Step-by-step explanation:
If the numbers are in AP then,
2(K + 3) = K - 1 + 3K - 1
=> 2K + 6 = 4K - 2
=> 2K = 8
=> K = 4
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