Question

if K + 1 = sec 2 Q (1 + sin Q) (1 + sin Q ) then find the value of x​

Answer 1

Answer:

sec

2

θ(1+sinθ)(1−sinθ)=k+1

sec

2

θ(1−sin

2

θ)=k (a+b)(a−b)=a

2

−b

2

example type

sec

2

θcos

2

θ=k

cos

2

θ

1

.cos

2

θ=k

k=1

hope this helps you

Answer 2

Answer:

If (k+1)=sec2θ(1+ sinθ)(1–sinθ), find k. check-circle. Text Solution . Answer : 0.