Question

If K + 1 = sec^2Q(1+sinQ)(1-SinQ), then find the value of K​

Answer 1

Answer:

Let theta be @

K+ 1 = sec square@ [ 1- sin@]{1 - sin@} K+ 1 = sec square@[1] - [sin square@} K+1 = sec square @[ cos square @] K+1=1 K=0

Hope this will help you...