Question

If k+1=sec square theta (1+sin theta) (1-sin theta) then find the value of k​

Answer 1

Answer:

sec

2

θ(1+sinθ)(1−sinθ)=k+1

sec

2

θ(1−sin

2

θ)=k (a+b)(a−b)=a

2

−b

2

sec

2

θcos

2

θ=k

cos

2

θ

1

.cos

2

θ=k

k=1

Step-by-step explanation:

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Answer 2

Answer:

K=1

Step-by-step explanation:

I have solved the sum in the picture attached above...kindly refer to that..

Hope you find it helpful :)